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kruskal.cpp
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82 lines (62 loc) · 1.6 KB
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// BOJ 1197 최소 스패닝 트리
#include <bits/stdc++.h>
#define sz size()
#define bk back()
#define fi first
#define se second
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
struct DisjointSet {
int n;
vector<int> dsu;
DisjointSet(int _n) {
n = _n;
dsu.resize(n + 1);
init();
}
void init() {
for (int i = 1; i <= n; i++)
dsu[i] = i;
}
int find(int z) {
if (z != dsu[z])
dsu[z] = find(dsu[z]);
return dsu[z];
}
void merge(int x, int y) { dsu[find(y)] = find(x); }
bool is_same(int x, int y) { return find(x) == find(y); }
};
struct Kruskal {
int n;
vector<pair<pii, int>> edges;
Kruskal(int n, vector<pair<pii, int>> edges) : n(n), edges(edges) {}
ll minimum_spanning_tree() {
sort(edges.begin(), edges.end(), [](pair<pii, int> p, pair<pii, int> q) { return p.se < q.se; });
DisjointSet ds(n);
ll ret = 0;
int cnt = 0;
for (pair<pii, int> p : edges) {
if (ds.is_same(p.fi.fi, p.fi.se))
continue;
ds.merge(p.fi.fi, p.fi.se);
ret += p.se;
cnt++;
if (cnt == n - 1)
break;
}
return ret;
}
};
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n, m;
cin >> n >> m;
vector<pair<pii, int>> edges(m);
for (int i = 0; i < m; i++)
cin >> edges[i].fi.fi >> edges[i].fi.se >> edges[i].se;
Kruskal kruskal(n, edges);
cout << kruskal.minimum_spanning_tree();
}