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11_Palindromic.cpp
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80 lines (73 loc) · 1.76 KB
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/**
* P436 最长回文子串
* 动态规划
*/
#include <iostream>
#include <vector>
#include <cstring>
#include <algorithm>
using namespace std;
// 输入 string
string targetStr;
// dp array
// 里面只能是 1 或者 0
int **dp;
void init()
{
cout << "Input the string: " << endl;
getline(cin, targetStr);
// initialize dp array
dp = new int*[targetStr.length()];
for (int i = 0; i < targetStr.length(); i++)
{
dp[i] = new int[targetStr.length()];
for (int j = 0; j < targetStr.length(); j++)
{
dp[i][j] = 0;
}
}
}
void calPalindromic()
{
// 记录当前最大回文子串的长度
int maxLength = 1;
// 设置边界条件
for (int i = 0; i < targetStr.length(); i++)
{
// 长度为 1 的子串,最大回文串值为 1
dp[i][i] = 1;
// 长度为 2 的子串,如果 str[i] == str[i][i + 1],最大回文串值为 2
if (i < targetStr.length() - 1)
{
dp[i][i + 1] = (targetStr[i] == targetStr[i + 1]) ? 1 : 0;
maxLength += 1;
}
}
// 状态转移
// 按字符串的长度进行枚举
for (int l = 3; l <= targetStr.length(); l++)
{
// 左端点 i
// 右端点 i + l - 3
for (int i = 0; i + l - 1 < targetStr.length(); i++)
{
if (targetStr[i] == targetStr[i + l - 1])
{
dp[i][i + l - 1] = dp[i + 1][i + l - 2];
// 最大回文子串长度 update
maxLength = l;
}
else
{
dp[i][i + l - 1] = 0;
}
}
}
cout << "Max Palindromic length: " << maxLength << endl;
}
int main()
{
init();
calPalindromic();
return 0;
}