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mob.java
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1236 lines (953 loc) · 29 KB
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import java.util.*;
public class mob{
public static void main(String[] args){
int[][] in = readPerm(args);
int[] sigma = in[0];
int[] pi = in[1];
System.out.print("Interval [");
printPerm(sigma,pi);
System.out.println("]");
int m = mob(sigma,pi);
int occ = NumOccurrences(sigma,pi);
int ne = NE(sigma,pi);
int s = secondPart(sigma,pi,m,ne);
ArrayList<String> lambdas = mobNEprint(sigma,pi);
System.out.println();
System.out.println("Mobius function = " + m);
System.out.println("<br>");
System.out.println("Number of Occurrences = " + occ);
System.out.println("Number of Normal Occurrences/Embeddings = " + ne);
System.out.println();
System.out.println("Value of second part s = " + s);
System.out.println();
if(lambdas.size() > 0) System.out.println("Lambdas in [sigma,pi) with nonzero mu(sigma,lambda)*EZ(lambda,sigma):");
for(int i = 0; i < lambdas.size(); i++) System.out.println(lambdas.get(i));
}
/***************************************************************/
//main methods for computing MF
private static int mob(int[] sigma, int[] pi){
if(!Contains(sigma,pi)) return 0;
if(Arrays.equals(sigma,pi)) return 1;
Interval I = new Interval(sigma,pi);
return I.Mobius();
}
//same as mobNE above but prints what each element of the formula contributes
private static ArrayList<String> mobNEprint(int[] sigma, int[] pi){
int[][] o = Occurrences(sigma,pi);
int[][] occ = occQuotient(o,pi);
int[] adjs = adjLocBoth(pi);
int num = 0;
//get all perms in the interval
Interval I = new Interval(sigma,pi);
//get all perms
ArrayList<int[]> perms = I.listAllPerms();
int s,mob,temp;
ArrayList<String> out = new ArrayList<String>();
//compute EZ(sigma,pi), add to num and print if EZ is none empty
String t = permString(perms.get(0));
s = incExSum(perms.get(0),pi,occ);
permString(perms.get(0));
if(s!=0){t += " : Contributes = " + s +" : product of mu = 1 and EZ = " + s;out.add(t);}
//loop through all elements of (sigma,pi)
for(int i = 1; i< perms.size(); i++){
t = "";
if(pi.length-perms.get(i).length>0){
//print lambda and compute EZ(lambda,pi)
s = incExSum(perms.get(i),pi);
if(!emptyEZ(perms.get(i),pi)){
t += permString(perms.get(i));
//if EZ is non empty compute mu(sigma,lambda) and print all
mob = mob(sigma,perms.get(i));
temp = s*mob;
t +=" : Contributes = " + temp + " : product of mu = " + mob + " and EZ = " + s;
if(temp!=0) out.add(t);
}
}
}
return out;
}
//Quotients the occurrences based upon equiv rel of differing only in adjacencies
private static int[][] occQuotient(int[][] occ,int[] pi){
//inc records whether to include occ[i] and is intialised to all 1's
int[] inc = new int[occ.length];
for(int i = 0; i < inc.length; i++) inc[i] = 1;
//find all the adjacency blocks
ArrayList<int[]> adjBl = maximalAdjBlocks(pi);
for(int i = 0; i < occ.length; i++){
for(int j = 0; j < adjBl.size(); j++){
//for each adjacency block look though the occurence at that block and see if there is a non zero letter to the left of a zero
// if ther is set that occurence to be not included.
for(int k = adjBl.get(j)[0]+1; k <= adjBl.get(j)[1]; k++){
if(!con(k,occ[i]) && con(k-1,occ[i])) inc[i] = 0;
}
}
}
//create a new array only including the quotiented occurences.
int count = 0;
for(int i = 0; i < inc.length; i++){ if(inc[i] == 1) count++;}
int[][] ret = new int[count][occ[0].length];
count = 0;
for(int i = 0; i < inc.length; i++){ if(inc[i] == 1){ret[count]=occ[i];count++;}}
return ret;
}
//returns number of normal occurrences
private static int NE(int[] sigma, int[] pi){
//get set of occurrences and positions of all tails of adjacencies
int[][] occ = Occurrences(sigma,pi);
int[] adjs = adjLocBoth(pi);
int num = 0;
//for each occurrence check if the all the tails appear in it, if so add 1 to num
for(int i = 0; i < occ.length; i++){
if(subArray(adjs,occ[i])) num++;
}
return num;
}
//returns the second part of the formula
private static int secondPart(int[] sigma, int[] pi,int mob,int NE){
//subtract sNE(sigma,pi) from mu(sigma,pi)
return (mob - (int)Math.pow(-1,pi.length-sigma.length)*NE);
}
//returns sum over EZ^{lambda,pi}
private static int incExSum(int[] lambda, int[] pi){
//get set of occurrences and tehen quotient them
int[][] o = Occurrences(lambda,pi);
int[][] occ = occQuotient(o,pi);
int num = 0;
//create a binary string which indicates which elements of occ to test if in EZ
long m = (long)Math.pow(2,occ.length);
int[] bin = new int[occ.length];
int s;
//intialise array as all 1's
for(int j = 0; j < bin.length; j++) bin[j] = 1;
//because EZ is upwards closed check if the set of all elemebts of occ are in EZ and if not then nothing is
if(!emptyZeroes(bin,occ,pi.length)) return 0;
//add (-1)^|S| for each S that has empty zero intersection, where S is displayed as a binary string relating to occ
for(long i = m-1; i > 0; i--){
bin = BinaryIntArray(i, occ.length);
s = sum(bin);
if(s!=1){
if(emptyZeroes(bin,occ,pi.length)){
//System.out.println(Arrays.toString(bin));
num += Math.pow(-1,s);
}
}
}
return num;
}
//returns true if EZ^{lambda,pi} is empty
private static boolean emptyEZ(int[] lambda, int[] pi){
int[][] o = Occurrences(lambda,pi);
int[][] occ = occQuotient(o,pi);
long m = (long)Math.pow(2,occ.length);
int[] bin = new int[occ.length];
for(int j = 0; j < bin.length; j++) bin[j] = 1;
if(!emptyZeroes(bin,occ,pi.length)) return true;
return false;
}
//returns true if EZ^{lambda,pi} is empty
private static boolean emptyEZ(int[] lambda, int[] pi,int[][] occ){
long m = (long)Math.pow(2,occ.length);
int[] bin = new int[occ.length];
for(int j = 0; j < bin.length; j++) bin[j] = 1;
if(!emptyZeroes(bin,occ,pi.length)) return true;
return false;
}
//returns sum over EZ^{lambda,pi}, same incExSum above to be used when occ is already known
private static int incExSum(int[] lambda, int[] pi, int[][] occ){
int num = 0;
long m = (long)Math.pow(2,occ.length);
int[] bin = new int[occ.length];
int s;
for(int j = 0; j < bin.length; j++) bin[j] = 1;
if(!emptyZeroes(bin,occ,pi.length)) return 0;
//add (-1)^|S| for each S that has empty zero intersection, where S is displayed as a binary string relating to occ
for(long i = m-1; i > 0; i--){
bin = BinaryIntArray(i, occ.length);
s = sum(bin);
if(s!=1){
if(emptyZeroes(bin,occ,pi.length)){
//System.out.println(Arrays.toString(bin));
num += Math.pow(-1,s);
}
}
}
return num;
}
private static ArrayList<int[]> EZ(int[] sigma,int[] pi){
//get occurrences and quotient;
int[][] o = Occurrences(sigma,pi);
int[][] occ = occQuotient(o,pi);
//init
long m = (long)Math.pow(2,occ.length);
int[] bin = new int[occ.length];
ArrayList<int[]> binList = new ArrayList<int[]>();
//add any nonzero sets to binList
for(long i = m-1; i > 0; i--){
bin = BinaryIntArray(i, occ.length);
if(sum(bin)!=1){
if(emptyZeroes(bin,occ,pi.length)){
binList.add(bin.clone());
}
}
}
return binList;
}
private static ArrayList<int[]> nonZeroEZ(int[] sigma,int[] pi){
//get occurrences and quotient;
int[][] o = Occurrences(sigma,pi);
int[][] occ = occQuotient(o,pi);
//init
long m = (long)Math.pow(2,occ.length);
int[] bin = new int[occ.length];
ArrayList<int[]> binList = new ArrayList<int[]>();
//add any nonzero sets to binList
for(long i = m-1; i > 0; i--){
bin = BinaryIntArray(i, occ.length);
if(sum(bin)!=1){
if(emptyZeroes(bin,occ,pi.length)){
binList.add(bin.clone());
}
}
}
return binList;
}
/***********************************************/
//printing methods
private static void printPerm(int[] perm){
if(perm.length < 10){
for(int i = 0; i < perm.length; i++){
System.out.print(perm[i]+1);
}
}
else{
for(int i = 0; i < perm.length; i++){
System.out.print(perm[i]+1 + " ");
}
}
}
private static void printPermln(int[] perm){
printPerm(perm);
System.out.println("");
}
private static void printPerm(int[] perm,int[] pi){
printPerm(perm);
System.out.print(" : ");
printPerm(pi);
System.out.print("");
}
private static void printPermln(int[] perm,int[] pi){
printPerm(perm);
System.out.print(" : ");
printPerm(pi);
System.out.println("");
}
//converts the permutation to a string
private static String permString(int[] a){
String ret = "";
for( int i = 0; i < a.length; i++) ret += (a[i]+1);
return ret;
}
/*********************************************/
//methods for reading a interval from input
//read two permutations
private static int[][] readPerm(String[] args){
int[] param = new int[args.length];
for(int k = 0; k < args.length; k++) param[k] = Integer.parseInt(args[k]);
int[] sigma = NumToPerm(param[0]);
int[] pi = PermOf(TailFrom(param, 1));
int[][] out = new int[][]{sigma,pi};
return out;
}
/**************************************************************/
//various methods needed for creating intervals
//produces the interval [sigma,pi] as a list of Level objects
private static ArrayList<Level> makeInterval(int[] sigma, int[] pi){
//create empty interval
ArrayList<Level> interval = new ArrayList<Level>();
//create and add top level containing pi
Level toplevel = new Level();
toplevel.add(pi);
interval.add(toplevel);
//add middle levels
for(int i = 0; i < pi.length - sigma.length - 1; i++){
Level nL = makelevel(interval.get(i),sigma);
interval.add(nL);
}
//create and add bottom level containing sigma
Level bottomlevel = new Level();
bottomlevel.add(sigma);
for(int i = 0; i < interval.get(interval.size()-1).length(); i++) bottomlevel.getPerm(0).addCover(i);
interval.add(bottomlevel);
return interval;
}
//makes a level of the poset
private static Level makelevel(Level above, int[] sigma){
Level newLevel = new Level();
newLevel.clear();
//loop through the above level remove each letter from each perm check it
//contains sigma and is not already present and then add it to the level
for(int k = 0; k < above.length(); k++){
for(int i = 0; i < above.get(k).length; i++){
int[] redperm = removeLetter(above.get(k),i);
if(Contains(sigma,redperm)){
//check if redperm is already in level, if not add it, if so record k as covering redperm
int c = newLevel.contains(redperm);
if(c == -1) newLevel.add(redperm,k);
else newLevel.getPerm(c).addCover(k);
}
}
}
return newLevel;
}
//remove letter and reduce all letters with higher value
private static int[] removeLetter(int[] perm, int index){
int[] newperm = new int[perm.length-1];
System.arraycopy(perm,0,newperm,0,index);
System.arraycopy(perm,index+1,newperm,index,perm.length-index-1);
for(int i = 0; i < newperm.length; i++){
if(newperm[i] > perm[index]) newperm[i]--;
}
return newperm;
}
//removes all letters perm[start]-perm[end] inclusive and reduces
private static int[] removeLetters(int[] perm, int start, int end){
int[] newperm = new int[perm.length-(end-start+1)];
System.arraycopy(perm,0,newperm,0,start);
System.arraycopy(perm,end+1,newperm,start,newperm.length-start);
return reduce(newperm);
}
//removes all letters at the positions in locs
private static int[] removeLetters(int[] perm, int[] locs){
int[] newperm = new int[perm.length-locs.length];
int t = 0;
for(int i = 0; i < perm.length; i++){
if(!con(i,locs)){
newperm[t] = perm[i];
t++;
}
}
return reduce(newperm);
}
/*********************************************************************/
//various methods used for computing MF
//sums the elements pi_start+...+pi_{end-1}
private static int sum(int start, int end, int[] pi){
int s = 0;
for(int i = start; i < end; i++) s += Math.abs(pi[i]);
return s;
}
//sums all elements of bin
private static int sum(int[] bin){
int s = 0;
for(int i = 0; i < bin.length; i++) s+=bin[i];
return s;
}
//sums abs of all elements of bin
private static int sumAbs(int[] bin){
int s = 0;
for(int i = 0; i < bin.length; i++) s+=Math.abs(bin[i]);
return s;
}
//returns true if the array pi contains the number i
private static boolean con(int i, int[] pi){
if(pi.length == 0) return false;
for(int j = 0; j < pi.length; j++){
if(pi[j] == i) return true;
}
return false;
}
//returns true if the array pi contains the number i
private static boolean con(int i, int[][] pi){
if(pi.length == 0) return false;
for(int j = 0; j < pi.length; j++){
if(pi[j] != null){
for(int k = 0; k < pi[j].length; k++){
if(pi[j][k] == i) return true;
if(pi[j][k] == i) return true;
}}
}
return false;
}
//lists all maximal Adjacency blocks in pi
private static ArrayList<int[]> maximalAdjBlocks(int[] pi){
int pos, j;
int i = 0;
ArrayList<int[]> out = new ArrayList<int[]>();
while(i < pi.length){
//sets pos to increasing or decreasing adj
if(i < pi.length-1 && pi[i] < pi[i+1]) pos = 1;
else pos = -1;
//finds how long adj is
j = i+1;
while(j < pi.length && pi[j-1] == pi[j]-pos) j++;
if(i == j-1) pos = 0;
//adds adj to out
out.add(new int[]{i,j-1, pos});
i = j;
}
return out;
}
//returns an array of all positions of perm in the tail of an adjacency
private static int[] adjLocBoth(int[] perm){
ArrayList<Integer> list = new ArrayList<Integer>();
for(int i = 1; i < perm.length; i++){
if(perm[i-1] == perm[i]-1){
list.add(i);
}
if(perm[i-1] == perm[i]+1){
list.add(i);
}
}
int[] arr = new int[list.size()];
for(int i = 0; i < list.size(); i++){
arr[i] = list.get(i);
}
return arr;
}
//returns the number of adjacencies
private static int Adj(int[] pi){
return maximalAdjBlocks(pi).size();
}
//checks that all of a is in b
private static boolean subArray(int[] a, int[] b){
if(b.length < a.length) return false;
int i = 0;
boolean found = false;
while(i < a.length){
int j = 0;
found = false;
while(j < b.length && !found){
if(a[i] == b[j]) found = true;
j++;
}
if(j == b.length && !found) return false;
i++;
}
return true;
}
//gives perm in reduced form
private static int[] reduce(int[] perm){
if(perm.length == 0) return perm;
int min = 0;
int max = 0;
int[] redperm = new int[perm.length];
for(int i = 0; i < perm.length; i++){ if(perm[i] > perm[max]) max = i;
if(perm[i] < perm[min]) min = i;}
redperm[min] = 0;
int count = 1;
int oldmin = min;
min = max;
while(count < perm.length){
for(int i = 0; i < perm.length; i++){
if(perm[i] < perm[min] && perm[i]>perm[oldmin]) min = i;
}
redperm[min] = count;
oldmin = min;
min = max;
count++;
}
return redperm;
}
//if the set S indicated by binary string bin has empty zero set intersection return true
private static boolean emptyZeroes(int[] bin, int[][] occ, int n){
for(int i = 0; i < n; i++){
boolean allZero = true;
for(int j = 0; j < bin.length; j++){
if(bin[j] == 1 && con(i,occ[j])) allZero = false;
}
if(allZero) return false;
}
return true;
}
//changes data to next permutation lexicographically and returns false if data is decreasing perm
private static boolean my_next_permutation(int[] data) {
int n=data.length;
int i,j,k,temp;
i=n-2;
while (i>=0 && data[i]>=data[i+1]) --i;
if (i<0) {
for (j=0,k=n-1; j<k; j++,k--) {
temp=data[j];
data[j]=data[k];
data[k]=temp;
}
return false;
}
j=n-1;
while (data[i]>=data[j]) --j;
temp=data[i];
data[i]=data[j];
data[j]=temp;
for (j=i+1,k=n-1; j<k; j++,k--) {
temp=data[j];
data[j]=data[k];
data[k]=temp;
}
return true;
}
/*************************************************************/
//various methods taken from e.java
private static int[] NumToPerm(int number){
int Dim;
for(Dim = 0; number/((int)Math.pow(10,Dim)) > 0; Dim++);
int[] perm = new int[Dim];
for(int k = Dim-1; k >= 0; k--){
perm[k] = number%10-1;
number = number/10;
}
return perm;
}
private static int[] TailFrom(int[] A, int start){
if(A == null)
return null;
int[] output = new int[A.length-start];
for(int k = start; k < A.length; k++)
output[k-start] = A[k];
return output;
}
private static int[] PermOf(int[] param){
int dim = param.length;;
if(dim == 1)
return StandardPerm(NumToPerm(param[0]));
return StandardPerm(param);
}
private static int[] StandardPerm(int[] perm){
if(perm == null)
return null;
return InvTableToPerm(InversionTable(perm));
}
private static int[] InvTableToPerm(int[] invTable){
if(invTable == null || invTable.length == 0)
return null;
int dim = invTable.length;
LinkedList<Integer> list = new LinkedList<Integer>();
for(int k = 0; k < dim; k++)
list.add(k);
int[] perm = new int[dim];
for(int k = 0; k < dim; k++){
perm[k] = (int)list.get(invTable[k]);
list.remove(invTable[k]);
}
return perm;
}
private static boolean Contains(int[] patt, int[] perm){
return !Avoids(patt, perm);
}
//returns number of occurrences
private static int NumOccurrences(int[] patt, int[] perm){
if(patt.length > perm.length)
return 0;
int sum = 0;
int[] set = new int[patt.length];
set[0] = -1;
while(NextKSubset(set, perm.length)){
if(Match(patt, SubSeq(set, perm)))
sum++;
}
return sum;
}
//returns set of occurrences
private static int[][] Occurrences(int[] patt, int[] perm){
if(patt.length > perm.length)
return null;
int[][] occurrences = new int[(int) LongChoose(perm.length, patt.length)][patt.length];
int[] set = new int[patt.length];
set[0] = -1;
int count = -1;
while(NextKSubset(set, perm.length)){
if(Match(patt, SubSeq(set, perm))){
count++;
for(int k = 0; k < patt.length; k++)
occurrences[count][k] = set[k];
}
}
count++;
int[][] output = new int[count][patt.length];
for(int n = 0; n < count; n++)
output[n] = occurrences[n];
return output;
}
private static boolean Avoids(int[] patt, int[] perm){
if(patt.length > perm.length) return true;
int pattLength = patt.length;
int dim = perm.length;
boolean[] string = FirstBinaryKString(dim, pattLength);
int[] invTable = InversionTable(patt);
if(Arrays.equals(invTable, InversionTable(SubSeq(string, perm)))) return false;
while(NextBinaryKString(string)){
if(Arrays.equals(invTable, InversionTable(SubSeq(string, perm)))){
return false;
}
}
return true;
}
private static boolean[] FirstBinaryKString(int n, int k){
if(n <= 0 || k > n || k < 0) return null;
boolean[] string = new boolean[n];
for(int i = 0; i < k; i++) string[i] = true;
return string;
}
private static int[] InversionTable(int[] perm){
if(perm == null || perm.length == 0) return null;
int[] table = new int[perm.length];
for(int k = 0; k < perm.length; k++){
for(int i = k+1; i < perm.length; i++){
if(perm[k] > perm[i])
table[k]++;
}
}
return table;
}
private static boolean NextBinaryKString(boolean[] string){
if(string == null) return false;
int dim = string.length;
int k = 0;
while(string[k] == false) k++;
int firstOne = k;
while(k < dim && string[k] == true){
string[k] = false;
k++;
}
if(k == dim) return false;
string[k] = true;
int numOnes = k - firstOne;
for(int i = 0; i < numOnes-1; i++)
string[i] = true;
return true;
}
private static int[] SubSeq(boolean[] string, int[] perm){
if(perm == null || string == null || string.length != perm.length) return null;
int numOnes = 0;
for(int k = 0; k < string.length; k++){
if(string[k]) numOnes++;
}
int[] output = new int[numOnes];
int count = 0;
for(int k = 0; k < string.length; k++){
if(string[k]) output[count++] = perm[k];
}
return output;
}
private static int[] SubSeq(int[] subset, int[] perm){
if(perm == null || subset == null || subset.length > perm.length)
return null;
int[] output = new int[subset.length];
for(int k = 0; k < subset.length; k++)
output[k] = perm[subset[k]];
return output;
}
private static boolean NextKSubset(int[] set, int dim){
if(set.length > dim)
return false;
if(set == null || set.length == 0)
return false;
int size = set.length;
if(set[0] == -1){//return the first set
for (int k = 0; k < size; k++)
set[k] = k;
return true;
}
int k = 1;
while(k < size && set[k] == set[k-1]+1)
k++;
if(k < size){//found an element exceeding its predecessor by > 1
set[k-1]++;
for(int i = 0; i < k-1; i++)
set[i] = i;
return true;
}
//k == size. if last element is maximal, we are done
if(set[k-1] == dim-1)
return false;
//last element is not maximal
set[k-1]++;
for(int i = 0; i < k-1; i++)
set[i] = i;
return true;
}
private static int Choose(int n, int k){
int adhoc, m;
if (k < 0 || k > n)
return(0);
if (k > (n / 2)) k = n - k;
adhoc = 1;
for (m = 0; m < k; m++)
adhoc = adhoc*(n-m);
return(adhoc / Factorial(k));
}
private static int Factorial(int n){
if (n < 0)
return(0);
if (n == 0)
return(1);
return n*Factorial(n-1);
}
private static long LongChoose(int n, int k){
long adhoc, m;
if (k < 0 || k > n)
return(0);
if (k > (n / 2)) k = n - k;
adhoc = 1;
for (m = 0; m < k; m++)
adhoc = adhoc*(n-m);
return(adhoc / LongFactorial(k));
}
private static long LongFactorial(int x) {
if (x < 0)
return 0;
long fact = 1;
while(x > 1) {
fact = fact * x;
x = x - 1;
}
return fact;
}
private static int iBit(int n, int i){
return (n >> i) & 01;
}
private static long iBit(long n, int i){
return (n >> i) & (long)01;
}
/** Does seq have a subsequence whose letters are in the same
relative order as those in patt, where we allow repeated letters in
both? **/
private static boolean Match(int[] patt, int[] seq){
if(patt.length != seq.length)
return false;
int dim = seq.length;
for(int n = 0; n < dim; n++)
for(int k = n+1; k < dim; k++)
if(Diff(patt[n], patt[k]) != Diff(seq[n], seq[k])) return false;
return true;
}
private static int Diff(int a, int b){
if(a < b)
return -1;
if(a == b)
return 0;
if(a > b)
return 1;
return -100;
}
private static int[] BinaryIntArray(int n, int dim){
int[] output = new int[dim];
for(int k = 0; k < dim; k++)
if(iBit(n,k) == 1)
output[k] = 1;
return output;
}
private static int[] BinaryIntArray(long n, int dim){
int[] output = new int[dim];
for(int k = 0; k < dim; k++)
if(iBit(n,k) == 1)
output[k] = 1;
return output;
}
//Interval Class
private static class Interval{
//interval is always of the form [sigma,pi], that is, sigma at bottom, pi at top
//inter contains all levels of the interval including pi at top and sigma at bottom
//note the levels are in decreasing lengths so inter.get(0) contains pi
private ArrayList<Level> inter = new ArrayList<Level>();
//create an empty interval
public Interval(){
ArrayList<Level> inter = new ArrayList<Level>();
}
//create the interval [sigma,pi]
public Interval(int[] sigma, int[] perm){
inter = makeInterval(sigma,perm);
}
//add a level at the bottom of the interval
public void add(Level l){
inter.add(l);
}