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RomanToInteger.java
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82 lines (77 loc) · 2.37 KB
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package Lc13_RomanToInteger;
import java.util.HashMap;
import java.util.Map;
/**
* 13. Roman to Integer
*
* Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M.
*
* Symbol Value
* I 1
* V 5
* X 10
* L 50
* C 100
* D 500
* M 1000
* For example, 2 is written as II in Roman numeral, just two ones added together. 12 is written as XII, which is simply
* X + II. The number 27 is written as XXVII, which is XX + V + II.
*
* Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII.
* Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same
* principle applies to the number nine, which is written as IX. There are six instances where subtraction is used:
*
* I can be placed before V (5) and X (10) to make 4 and 9.
* X can be placed before L (50) and C (100) to make 40 and 90.
* C can be placed before D (500) and M (1000) to make 400 and 900.
*
* Given a roman numeral, convert it to an integer.
*
* Example 1:
* Input: s = "III"
* Output: 3
* Explanation: III = 3.
*
* Example 2:
* Input: s = "LVIII"
* Output: 58
* Explanation: L = 50, V= 5, III = 3.
*
* Example 3:
* Input: s = "MCMXCIV"
* Output: 1994
* Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.
*
* Constraints:
* 1 <= s.length <= 15
* s contains only the characters ('I', 'V', 'X', 'L', 'C', 'D', 'M').
* It is guaranteed that s is a valid roman numeral in the range [1, 3999].
*/
public class RomanToInteger {
Map<Character, Integer> symbolValues = new HashMap<Character, Integer>() {{
put('I', 1);
put('V', 5);
put('X', 10);
put('L', 50);
put('C', 100);
put('D', 500);
put('M', 1000);
}};
public int romanToInt(String s) {
int ans = 0;
for (int i = 0; i < s.length(); i++) {
if (i == s.length() - 1) {
ans += symbolValues.get(s.charAt(i));
break;
}
Integer prev = symbolValues.get(s.charAt(i));
Integer next = symbolValues.get(s.charAt(i + 1));
if (prev < next) {
ans -= prev;
} else {
ans += prev;
}
}
return ans;
}
}