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dominator_tree.cpp
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170 lines (161 loc) · 3.81 KB
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#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template <class T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define int long long int
#define pb push_back
#define pi pair<int, int>
#define pii pair<int, pi>
#define fir first
#define sec second
#define MAXN 200005
#define mod 998244353
struct dominator_tree
{
int n, t;
vector<vector<int>> g, tree, rg, bucket;
vector<int> dfs_l, dfs_r, idom, sdom, prv, pre, ancestor, label, preorder;
dominator_tree(vector<vector<int>> &adj, int source)
{
int n = adj.size();
g = adj;
tree.resize(n);
rg.resize(n);
bucket.resize(n);
dfs_l.resize(n);
dfs_r.resize(n);
idom.resize(n);
sdom.assign(n, -1);
prv.resize(n);
pre.assign(n, -1);
ancestor.assign(n, -1);
label.resize(n);
build(source);
}
void dfs(int v)
{
pre[v] = ++t;
sdom[v] = label[v] = v;
preorder.pb(v);
for (auto const &nxt : g[v])
{
if (sdom[nxt] == -1)
{
prv[nxt] = v;
dfs(nxt);
}
rg[nxt].pb(v);
}
}
int eval(int v)
{
if (ancestor[v] == -1)
return v;
if (ancestor[ancestor[v]] == -1)
return label[v];
int u = eval(ancestor[v]);
if (pre[sdom[u]] < pre[sdom[label[v]]])
label[v] = u;
ancestor[v] = ancestor[u];
return label[v];
}
void dfs2(int v)
{
dfs_l[v] = t++;
for (auto const &nxt : tree[v])
{
dfs2(nxt);
}
dfs_r[v] = t++;
}
void build(int s)
{
t = 0;
dfs(s);
if (preorder.size() == 1)
{
return;
}
int sz = preorder.size();
for (int i = sz - 1; i >= 1; i--)
{
int w = preorder[i];
for (auto const &v : rg[w])
{
int u = eval(v);
if (pre[sdom[u]] < pre[sdom[w]])
sdom[w] = sdom[u];
}
bucket[sdom[w]].push_back(w);
ancestor[w] = prv[w];
for (auto const &v : bucket[prv[w]])
{
int u = eval(v);
idom[v] = (u == v) ? sdom[v] : u;
}
bucket[prv[w]].clear();
}
for (int i = 1; i < preorder.size(); i++)
{
int w = preorder[i];
if (idom[w] != sdom[w])
idom[w] = idom[idom[w]];
tree[idom[w]].push_back(w);
}
idom[s] = sdom[s] = -1;
t = 0;
dfs2(s);
}
bool dominates(int u, int v)
{
if (pre[v] == -1)
return 1;
return dfs_l[u] <= dfs_l[v] && dfs_r[v] <= dfs_r[u];
}
};
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int n, m;
cin >> n >> m;
vector<vector<int>> adj(n);
for (int i = 0; i < m; i++)
{
int a, b;
cin >> a >> b;
a--, b--;
adj[a].pb(b);
}
dominator_tree d(adj, 0);
vector<int> ans;
for (int i = 0; i < n; i++)
{
if (d.dominates(i, n - 1))
ans.pb(i);
}
cout << ans.size() << endl;
for (int i = 0; i < ans.size(); i++)
cout << ans[i] + 1 << " \n"[i == ans.size() - 1];
}
// https://tanujkhattar.wordpress.com/2016/01/11/dominator-tree-of-a-directed-graph/
// https://cses.fi/problemset/task/1703/ (problema desse codigo)
// https://codeforces.com/gym/100513/problem/L
// https://codeforces.com/contest/757/problem/F
// dado um vertice source s
// dizemos que u domina w, se todos os caminhos de
// s ate w passam pelo vertice u
// dizemos que u é um dominador imediato de w se u domina w
// e todos os demais dominadores de w, dominam u
// 1 - todo vertice (tirando o source) tem um dominador
// pois o source domina todos os demais vertices
// 2 - todo vertice (tirando o source) tem exatamente um
// unico dominador imediato
// se eu crio um grafo com todas as arestas do tipo
// (dominador imediato de w) - w
// para todos os vertices w que nao sao a source
// esse grafo eh uma arvore
// e eh a dominator tree