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substring_fft.cpp
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121 lines (117 loc) · 2.65 KB
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#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template <class T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define PI acos(-1)
#define int long long int
#define pb push_back
#define pi pair<int, int>
#define pii pair<pi, int>
#define fir first
#define sec second
#define MAXN 100005
#define mod 1000000007
#define cd complex<double>
const double eps = 1e-12;
const int alphabet_size = 26;
namespace fft
{
void dft(vector<cd> &a)
{
int n = a.size();
if (n == 1)
return;
vector<cd> a0(n / 2), a1(n / 2);
for (int i = 0; 2 * i < n; i++)
{
a0[i] = a[2 * i];
a1[i] = a[2 * i + 1];
}
dft(a0);
dft(a1);
double ang = 2 * PI / n;
cd w(1), wn(cos(ang), sin(ang));
for (int i = 0; 2 * i < n; i++)
{
a[i] = a0[i] + w * a1[i];
a[i + n / 2] = a0[i] - w * a1[i];
w *= wn;
}
}
void inverse_dft(vector<cd> &a)
{
int n = a.size();
if (n == 1)
return;
vector<cd> a0(n / 2), a1(n / 2);
for (int i = 0; 2 * i < n; i++)
{
a0[i] = a[2 * i];
a1[i] = a[2 * i + 1];
}
inverse_dft(a0);
inverse_dft(a1);
double ang = 2 * PI / n * -1;
cd w(1), wn(cos(ang), sin(ang));
for (int i = 0; 2 * i < n; i++)
{
a[i] = a0[i] + w * a1[i];
a[i + n / 2] = a0[i] - w * a1[i];
a[i] /= 2;
a[i + n / 2] /= 2;
w *= wn;
}
}
vector<double> mul(vector<cd> a, vector<cd> b)
{
int n = 1;
vector<cd> fa(a.begin(), a.end()), fb(b.begin(), b.end());
while (n < a.size() + b.size())
n <<= 1;
fa.resize(n);
fb.resize(n);
dft(fa);
dft(fb);
for (int i = 0; i < n; i++)
fa[i] *= fb[i];
inverse_dft(fa);
vector<double> ans(n);
for (int i = 0; i < n; i++)
ans[i] = fa[i].real();
return ans;
}
} // namespace fft
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
string s, t;
cin >> s >> t;
int n = s.size(), m = t.size();
reverse(t.begin(), t.end());
vector<cd> a(n);
vector<cd> b(m);
for (int i = 0; i < n; i++)
{
int ch = s[i] - 'a';
double ang = (2 * PI * ch) / alphabet_size;
a[i] = cd(cos(ang), sin(ang));
}
for (int i = 0; i < m; i++)
{
int ch = t[i] - 'a';
double ang = (2 * PI * ch) / alphabet_size;
b[i] = cd(cos(ang), -sin(ang));
}
vector<double> ans = fft::mul(a, b);
int matches = 0;
for (int i = m - 1; i < n; i++)
matches += (abs(ans[i] - m) <= eps);
cout << matches << endl;
return 0;
}
// number of matches of a pattern in string
// using fft