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suffix_array.cpp
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118 lines (114 loc) · 2.57 KB
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#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template <class T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define int long long int
#define endl '\n'
#define pb push_back
#define pi pair<int, int>
#define pii pair<pi, int>
#define pci pair<char, int>
#define fir first
#define sec second
#define MAXN 500001
#define mod 1000000007
vector<int> suffix_array(string s)
{
s += "$"; // menor do que todos os chars da string st
int n = s.size(), N = max(n + 1, 260ll);
vector<int> sa(n), ra(n);
for (int i = 0; i < n; i++)
{
sa[i] = i, ra[i] = s[i];
}
for (int k = 0; k < n; k ? k *= 2 : k++)
{
vector<int> nsa(sa), nra(n), cnt(N);
for (int i = 0; i < n; i++)
{
nsa[i] = (nsa[i] - k + n) % n;
cnt[ra[i]]++;
}
for (int i = 1; i < N; i++)
{
cnt[i] += cnt[i - 1];
}
for (int i = n - 1; i + 1; i--)
{
sa[--cnt[ra[nsa[i]]]] = nsa[i];
}
for (int i = 1, r = 0; i < n; i++)
{
nra[sa[i]] = r += (ra[sa[i]] != ra[sa[i - 1]] || ra[(sa[i] + k) % n] != ra[(sa[i - 1] + k) % n]);
}
ra = nra;
if (ra[sa[n - 1]] == n - 1)
break;
}
return vector<int>(sa.begin() + 1, sa.end());
}
vector<int> kasai(string s, vector<int> sa)
{
int n = s.size(), k = 0;
vector<int> ra(n), lcp(n);
for (int i = 0; i < n; i++)
{
ra[sa[i]] = i;
}
for (int i = 0; i < n; i++, k -= !!k)
{
if (ra[i] == n - 1)
{
k = 0;
continue;
}
int j = sa[ra[i] + 1];
while (i + k < n and j + k < n and s[i + k] == s[j + k])
k++;
lcp[ra[i]] = k;
}
return lcp;
}
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
string s;
cin >> s;
int n = s.size();
vector<int> p = suffix_array(s);
vector<int> lcp = kasai(s, p);
for (int i = 0; i < s.size(); i++) // sufix array
cout << p[i] << " ";
cout << endl;
for (int i = 0; i + 1 < s.size(); i++) // lcp entre 2 suffixos adjacentes no suffix array
cout << lcp[i] << " ";
cout << endl;
int q;
cin >> q;
while (q--)
{
string t;
cin >> t;
int i = 0, f = n - 1, m, lb, ub;
while (i < f)
{
m = (i + f) / 2;
(t <= s.substr(p[m], t.size())) ? f = m : i = m + 1;
}
ub = i, i = 0, f = n - 1;
while (i < f)
{
m = (i + f) / 2;
(t >= s.substr(p[m], t.size())) ? i = m + 1 : f = m;
}
lb = i;
if (s.substr(p[lb], t.size()) == t)
lb++;
cout << lb - ub << endl;
}
return 0;
}