lesson-1 is done #1
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Hello @DoctorChe! Thanks for opening this PR. We checked the lines you've touched for PEP 8 issues, and found:
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| print(f"Введено число {d3}{d2}{d1}") | ||
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| print(f"Сумма цифр введённого числа = {d3 + d2 + d1}") | ||
| print(f"Произведение цифр введённого числа = {d3 * d2 * d1}") |
| print(f"Побитовая операция исключительное ИЛИ над числами 5 и 6: (5 ^ 6) = {5 ^ 6}") | ||
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| print(f"Побитовый сдвиг влево над числом 5 на два знака: (5 << 2) = {5 << 2}") | ||
| print(f"Побитовый сдвиг вправо над числом 5 на два знака: (5 >> 2) = {5 >> 2}") |
| if b >= 0: | ||
| print(f"Уравнение прямой: y = {k}x + {b}") | ||
| else: | ||
| print(f"Уравнение прямой: y = {k}x - {b * -1}") |
| s = chr(abs(int(random() * (ord(s2) - ord(s1) + 1)) + ord(s1))) | ||
| else: | ||
| s = chr(abs(int(random() * (ord(s1) - ord(s2) + 1)) + ord(s2))) | ||
| print(f"Случайный символ в диапазоне от {s1} до {s2}: {s}") |
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да, здесь можно исп-ть встроенные ф-ции
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| print(f"Первая буква находится на {s1 - first + 1}-м месте алфавита") | ||
| print(f"Первая буква находится на {s2 - first + 1}-м месте алфавита") | ||
| print(f"Между этими буквами находится {count} букв(а)") |
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работает отлично, в том числе и при обратном порядке букв
| # 6. Пользователь вводит номер буквы в алфавите. Определить, какая это буква. | ||
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| s = int(input("Введте номер буквы в алфавите: ")) | ||
| print(f"Буква под номером {s} - это \"{chr(s + ord('a') - 1)}\"") |
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хорошо.
+, что везде исп-ся ф-строки
| elif (l1 == l2) or (l2 == l3) or (l1 == l3): | ||
| print("Треугольник является равнобедренным") | ||
| else: | ||
| print("Такого треугольника не существует") |
| if (year % 4 == 0 and year % 100 != 0) or year % 400 == 0: | ||
| print(f"Год {year} является високосным") | ||
| else: | ||
| print(f"Год {year} не високосный") |
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отлично, вижу группировку условий
| elif b < a < c or b > a > c: | ||
| print(f"Средним является число {a}") | ||
| else: | ||
| print(f"Среди введённых чисел нет среднего числа") |
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