lesson-2 is done #2
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Hello @DoctorChe! Thanks for updating this PR. We checked the lines you've touched for PEP 8 issues, and found:
Comment last updated at 2019-05-21 07:48:39 UTC |
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| print("\nРасчёт через рекурсию") | ||
| calc() |
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задание выполнено, отдельное спасибо за рекурсию
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| print("\nРасчёт через рекурсию") | ||
| even_odd(input_number) |
| print(f"Обратное число {revers_recursion(number)}") | ||
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| print("\nРасчёт через рекурсию") | ||
| print(f"Обратное число {revers_recursion(number)}") |
| print(f"Сумма {n} чисел из ряда 1 -0.5 0.25 -0.125 ... равна {sum_range_n(n)}") | ||
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| print("\nРасчёт через рекурсию") | ||
| print(f"Сумма {n} чисел из ряда 1 -0.5 0.25 -0.125 ... равна {sum_range_n_recursion(n)}") |
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| print("\n\nРасчёт через рекурсию") | ||
| print_ascii_table() |
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спасибо. хорошо что любой перебор можно реализовать и циклом, и рекурсией
но надо помнить о ресурсах
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| print("\nРасчёт через рекурсию") | ||
| rand_number = int(random() * max_number + 1) | ||
| guess_number_recursion(rand_number) |
| else: | ||
| print(f"1+2+...+{n} = {sum_range_n}") | ||
| print(f"n(n+1)/2 = {sum_n}") | ||
| print(f"1+2+...+{n} <> n(n+1)/2") |
| print(f"Цифра {my_digit} встречается {loop(n, my_digit)} раз(а)") | ||
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| print("\nРасчёт через рекурсию") | ||
| print(f"Цифра {my_digit} встречается {recursion(n, my_digit)} раз(а)") |
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здесь в принципе можно только циклом ограничиться
| print(f"Наибольшее число по сумме цифр {b}") | ||
| print(f"Сумма его цифр равна: {sum_digits_b}") | ||
| else: | ||
| print(f"Суммы цифр введённых чисел равны") |
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