Duplicate contexts do not throw IllegalArgumentException [EXTERNAL ISSUE]

[Katsute]

Prerequisites

If all checks are not passed then the issue will be closed

• I have checked that no other similar issue already exists

Operating System: Operating system name and version
Windows 10

Release Version: Release version or branch where the issue occurred
03.05.06

Issue

Explain your issue. Add any screenshots here
Duplicate contexts do not throw IllegalArgumentException.
Issue is caused by HttpServer; this is not a SimpleHttpServer issue.

Expected Behavior

Explain what was supposed to happen
Duplicate contexts should throw IllegalArgumentException.

Steps To Reproduce

Explain how and/or when the error occurred
Use createContext on same context using HttpServer.

[Katsute]

Multiple tests have been run against the #create method in the sun http server library; but the illargs exception is only thrown for specific contexts, not all. This is a dependency issue and can not be resolved by SimpleHttpServer

[Katsute]

According to the source code an IllegalArgumentException is never thrown for duplicate contexts. The documentation on this method is invalid.

sun.net.httpserver.ServerImpl

...
    public synchronized HttpContextImpl createContext (String path, HttpHandler handler) {
        if (handler == null || path == null) {
            throw new NullPointerException ("null handler, or path parameter");
        }
        HttpContextImpl context = new HttpContextImpl (protocol, path, handler, this);
        contexts.add (context);
        logger.log (Level.DEBUG, "context created: " + path);
        return context;
    }
...

sun.net.httpserver.HttpContextImpl

...
    HttpContextImpl (String protocol, String path, HttpHandler cb, ServerImpl server) {
        if (path == null || protocol == null || path.length() < 1 || path.charAt(0) != '/') {
            throw new IllegalArgumentException ("Illegal value for path or protocol");
        }
        this.protocol = protocol.toLowerCase();
        this.path = path;
        if (!this.protocol.equals ("http") && !this.protocol.equals ("https")) {
            throw new IllegalArgumentException ("Illegal value for protocol");
        }
        this.handler = cb;
        this.server = server;
        authfilter = new AuthFilter(null);
        sfilters.add (authfilter);
    }
...