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better error message for missing j in cube #4282

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Merged
mattdowle merged 4 commits into from
Apr 15, 2021
Merged

better error message for missing j in cube #4282

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c282ec4
better error message for missing j in cube
MichaelChirico Mar 6, 2020
4e29ada
fixed, thanks jan
MichaelChirico Mar 7, 2020
4e88b47
Merge branch 'master' into cube-missing-j
mattdowle Apr 15, 2021
1e9c8ec
news item: move subject (cube) to be first word
mattdowle Apr 15, 2021
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2 changes: 2 additions & 0 deletions NEWS.md
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Expand Up @@ -30,6 +30,8 @@

3. In v1.12.4, fractional `fread(..., stringsAsFactors=)` was added. For example if `stringsAsFactors=0.2`, any character column with fewer than 20% unique strings would be cast as `factor`. This is now documented in `?fread` as well, [#4706](https://github.com/Rdatatable/data.table/issues/4706). Thanks to @markderry for the PR.

4. `cube(DT, by="a")` now gives a more helpful error that `j` is missing, [#4282](https://github.com/Rdatatable/data.table/pull/4282).


# data.table [v1.14.0](https://github.com/Rdatatable/data.table/milestone/23?closed=1) (21 Feb 2021)

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4 changes: 3 additions & 1 deletion R/groupingsets.R
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Expand Up @@ -27,10 +27,12 @@ cube.data.table = function(x, j, by, .SDcols, id = FALSE, ...) {
stop("Argument 'by' must be a character vector of column names used in grouping.")
if (!is.logical(id))
stop("Argument 'id' must be a logical scalar.")
if (missing(j))
stop("Argument 'j' is required")
# generate grouping sets for cube - power set: http://stackoverflow.com/a/32187892/2490497
n = length(by)
keepBool = sapply(2L^(seq_len(n)-1L), function(k) rep(c(FALSE, TRUE), times=k, each=((2L^n)/(2L*k))))
sets = lapply((2L^n):1L, function(j) by[keepBool[j, ]])
sets = lapply((2L^n):1L, function(jj) by[keepBool[jj, ]])
# redirect to workhorse function
jj = substitute(j)
groupingsets.data.table(x, by=by, sets=sets, .SDcols=.SDcols, id=id, jj=jj)
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3 changes: 3 additions & 0 deletions inst/tests/tests.Rraw
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Expand Up @@ -17295,3 +17295,6 @@ test(2165.3, X[Y], data.table(A=2:3, B=2:3, i.A=2:1, ke
test(2165.4, X[Y, on=.(A)], data.table(A=2:1, B=c(2L,NA), i.B=2:3)) # no key
test(2165.5, X[Y, on=.(A), x.B, by=.EACHI], data.table(A=2:1, x.B=c(2L,NA))) # no key

# missing j was caught in groupingsets but not cube, leading to unexpected error message, #4282
DT = data.table(a=1)
test(2166, cube(DT, by='a'), error="Argument 'j' is required")