Create spiralPrint.py

matrix/spiralPrint.py

@@ -0,0 +1,66 @@
+"""
+This program print the matix in spiral form.
+This problem has been solved through recursive way.
+
+      Matrix must satisfy below conditions
+        i) matrix should be only one or two dimensional
+        ii)column of all the row should be equal
+"""
+def checkMatrix(a):
+    # must be
+    if type(a) == list and len(a) > 0:
+        if type(a[0]) == list:
+            prevLen = 0
+            for i in a:
+                if prevLen == 0:
+                    prevLen = len(i)
+                    result = True
+                elif prevLen == len(i):
+                    result = True
+                else:
+                    result = False
+        else:
+            result = True
+    else:
+        result = False
+    return result
+
+
+def spiralPrint(a):
+
+    if checkMatrix(a) and len(a) > 0:
+
+        matRow = len(a)
+        if type(a[0]) == list:
+            matCol = len(a[0])
+        else:
+            for dat in a:
+                print(dat),
+            return
+
+        # horizotal printing increasing
+        for i in range(0, matCol):
+            print(a[0][i]),
+        # vertical printing down
+        for i in range(1, matRow):
+            print(a[i][matCol - 1]),
+        # horizotal printing decreasing
+        if matRow > 1:
+            for i in range(matCol - 2, -1, -1):
+                print(a[matRow - 1][i]),
+        # vertical printing up
+        for i in range(matRow - 2, 0, -1):
+            print(a[i][0]),
+        remainMat = [row[1:matCol - 1] for row in a[1:matRow - 1]]
+        if len(remainMat) > 0:
+            spiralPrint(remainMat)
+        else:
+            return
+    else:
+        print("Not a valid matrix")
+        return
+
+
+# driver code
+a = [[1 , 2, 3, 4],[5, 6, 7, 8],[9, 10, 11, 12]]
+spiralPrint(a)