Image.open() not working for URL

[irfanumar1994]

url = "https://www.linkpicture.com/q/knots_SM.jpg"
image_data = Image.open(requests.get(url, stream=True).raw)

This does not worked for me and yield error "cannot identify image file <_io.BytesIO object at 0x7f9a16b12a98>"

I have tried other workaround mentioned here but that also not working

[KennyTC]

It worked for me

from PIL import Image
import requests
from io import BytesIO

url = 'https://cdn.britannica.com/30/136130-050-3370E37A/Leopard.jpg'
response = requests.get(url)
image_data = Image.open(BytesIO(response.content))