assignment_one

02_activities/assignments/assignment1.sql

@@ -4,20 +4,25 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+SELECT * FROM customer
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
+SELECT * FROM customer
+ORDER BY customer_last_name, customer_first_name
+LIMIT 10
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
-
+SELECT * FROM customer_purchases
+WHERE product_id IN (4,9)
 
 -- option 2
+SELECT * FROM customer_purchases
+WHERE product_id = 4 OR product_id = 9;
 
 
 
@@ -27,10 +32,14 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
-
+SELECT *, quantity * cost_to_customer_per_qty as price 
+FROM customer_purchases
+WHERE vendor_id <=10 AND vendor_id >=8
 
 -- option 2
-
+SELECT *, quantity * cost_to_customer_per_qty as price 
+FROM customer_purchases
+WHERE vendor_id BETWEEN 8 AND 10
 
 
 --CASE
@@ -39,19 +48,38 @@ Using the product table, write a query that outputs the product_id and product_n
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
 
-
+SELECT product_id, product_name, product_qty_type,
+	CASE 
+		WHEN product_qty_type = 'unit' THEN 'unit'
+		ELSE 'bulk'
+	END AS prod_qty_type_condensed
+FROM product;
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
 
-
+SELECT product_id, product_name, product_qty_type,
+	CASE 
+		WHEN product_qty_type = 'unit' THEN 'unit'
+		ELSE 'bulk'
+	END AS prod_qty_type_condensed,
+product_name,
+	CASE 
+		WHEN lower(product_name) LIKE "%pepper%" THEN 1
+		ELSE 0
+	END AS pepper_flag
+FROM product;
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
-
+SELECT * 
+FROM vendor as v
+INNER JOIN vendor_booth_assignments as vba
+ON v.vendor_id = vba.vendor_id
+ORDER BY vendor_name, market_date
 
 
 /* SECTION 3 */
@@ -60,14 +88,24 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
-
+SELECT vendor_id, count(booth_number) as total_booth_assignments
+FROM vendor_booth_assignments 
+GROUP BY vendor_id
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
 of customers for them to give stickers to, sorted by last name, then first name. 
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
+SELECT customer_last_name, customer_first_name, 
+'$' || ROUND(SUM(cp.quantity * cp.cost_to_customer_per_qty),2) AS total_purchases
+FROM customer AS c
+LEFT JOIN customer_purchases AS cp
+ON c.customer_id = cp.customer_id
+GROUP BY c.customer_id
+HAVING total_purchases > 2000
+ORDER BY c.customer_last_name, c.customer_first_name
 
 
 --Temp Table
@@ -82,14 +120,31 @@ When inserting the new vendor, you need to appropriately align the columns to be
 VALUES(col1,col2,col3,col4,col5) 
 */
 
-
+CREATE TEMP TABLE temp.new_vendor AS
+SELECT * FROM vendor;
+
+INSERT INTO temp.new_vendor (
+  vendor_id, 
+  vendor_name, 
+  vendor_type, 
+  vendor_owner_first_name, 
+  vendor_owner_last_name
+)
+VALUES (
+  10, 
+  'Thomass Superfood Store', 
+  'Fresh Focused', 
+  'Thomas', 
+  'Rosenthal'
+);
 
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
 
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
 and year are! */
-
+SELECT customer_id, strftime('%m', market_date) as month, strftime('%Y', market_date) as year
+FROM customer_purchases
 
 
 /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
@@ -98,3 +153,7 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
 
+SELECT customer_id, '$' || ROUND(SUM(quantity * cost_to_customer_per_qty),2) AS total_purchases
+FROM customer_purchases
+WHERE strftime('%m', market_date) = '04' AND strftime('%Y', market_date) = '2022' 
+GROUP BY customer_id