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support select distinct with aggregate like this:

SELECT
      DISTINCT dt,
      count(dt2) over (partition by dt) as num
      from
      (select 1 as dt,2 as dt2)t
group by dt,dt2;

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Since 2024-03-18, the Document has been moved to doris-website.
See Doris Document.

@github-actions github-actions bot added the approved Indicates a PR has been approved by one committer. label May 14, 2024
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PR approved by at least one committer and no changes requested.

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PR approved by anyone and no changes requested.

@924060929
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run buildall

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5 participants