operator unsigned long() const; is missing

[dirkx]

The declaration for:

operator unsigned long() const;

appears to be missing

[aentinger]

Hi @dirkx ☕ 👋

I'm not deeply familiar with this code base. Where do you think its missing? Can you provide a PR to fix this?

Cheers, Alex

[dirkx]

Why I think it is missing -- because the analog of unsigned int = json["key1"]; for an unsigned long is:L unsigned long foo = json["key2"]; and that will fail without it :) Will see if I can do a one line PR. Dw.