Erroneous assertion not breaking the Scenario

[vinicius978]

What are you trying to achieve?

I'm trying to do an assertion in a test Scenario with 2 values taken from two different pages on a website

What do you get instead?

Even forcing the assertion to fail, test keeps outputting that it PASSED.

A snippet of the assertion part:

        let assert = require('assert');
        I.say('Assertion...');
        assert.true(value1 == (value2 + value3));

I need like a I.assertThat(expression) in order for the test to fail when values don't match.
Right now I'm researching about assertions on codecept and trying to figure out a solution for that.

Details

• CodeceptJS version: 1.1.1
• NodeJS Version: 9.4.0
• Operating System: Linux Mint
• WebDriverIO

[reubenmiller]

I looked at the package.json and found no dependency to 'assert', so they must be using the node assert library. https://nodejs.org/api/assert.html

As per the node js docs, there is no .true property, so unless you're using another assert library (or I'm reading the docs wrong).

Though I've been using the chai (http://chaijs.com/api/bdd/) expect/should module in my project with success. Here's an example.

const { expect } = require('chai');
expect(true).to.be.true;

[vinicius978]

Thanks for that, appreciate it!

BTW, in order to build a structure like I.AssertThat(expression), do I need to create a Helper?

[reubenmiller]

Yes implementing it in a Helper is one way of doing it, and probably the most common. The other option is to define a StepObject, which also allows you to use I.AssertThat(expression), and the StepObject can also import additional PageObjects if required.

[reubenmiller]

I would suggest looking at the source code for the Helpers i.e. in ./lib/helper/WebDriverIO.js. They provide great examples on how to do it.

i.e. this is from the WebDriverIO.js Helper

  async seeInTitle(text) {
    const title = await this.browser.getTitle();
    return stringIncludes('web page title').assert(text, title);
  }

[reubenmiller]

Can you please close the issue if your original question has now been answered.