第一组第二周代码作业

group01/1298552064/.classpath

@@ -0,0 +1,8 @@
+<?xml version="1.0" encoding="UTF-8"?>
+<classpath>
+	<classpathentry kind="src" path="src"/>
+	<classpathentry kind="con" path="org.eclipse.jdt.launching.JRE_CONTAINER"/>
+	<classpathentry kind="con" path="org.eclipse.jdt.junit.JUNIT_CONTAINER/4"/>
+	<classpathentry kind="lib" path="src/dom4j-1.6.1.jar"/>
+	<classpathentry kind="output" path="bin"/>
+</classpath>

group01/1298552064/.gitignore

@@ -0,0 +1 @@
+/bin/

group01/1298552064/.project

@@ -0,0 +1,17 @@
+<?xml version="1.0" encoding="UTF-8"?>
+<projectDescription>
+	<name>1298552064Learning</name>
+	<comment></comment>
+	<projects>
+	</projects>
+	<buildSpec>
+		<buildCommand>
+			<name>org.eclipse.jdt.core.javabuilder</name>
+			<arguments>
+			</arguments>
+		</buildCommand>
+	</buildSpec>
+	<natures>
+		<nature>org.eclipse.jdt.core.javanature</nature>
+	</natures>
+</projectDescription>

group01/1298552064/src/week01/basic/MyLinkedList.java

@@ -124,7 +124,7 @@ public Object removeLast() {
 			Node p = head;
 			for (int i = 0; i < size; i++) {
 				if (p.next.next == null) {
-					removeObject = p.next;
+					removeObject = p.next.data;
 					p.next = null;
 					break;
 				} else {

group01/1298552064/src/week02/array/ArrayUtil.java

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+package week02.array;
+
+import java.util.Arrays;
+
+public class ArrayUtil {
+
+	// 工具类，不予许创建实例
+	private ArrayUtil() {
+	}
+
+	/**
+	 * 给定一个整形数组a , 对该数组的值进行置换 例如： a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7] 如果 a =
+	 * [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7]
+	 * 
+	 * @param origin
+	 * @return
+	 */
+	public static void reverseArray(int[] origin) {
+		if (origin != null && origin.length > 0) {
+			int temp = 0;
+
+			// 数组首尾元素置换
+			for (int i = 0; i < origin.length / 2; i++) {
+				temp = origin[i];
+				origin[i] = origin[origin.length - i - 1];
+				origin[origin.length - i - 1] = temp;
+			}
+		}
+	}
+
+	/**
+	 * 现在有如下的一个数组： int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5}
+	 * 要求将以上数组中值为0的项去掉，将不为0的值存入一个新的数组，生成的新数组为： {1,3,4,5,6,6,5,4,7,6,7,5}
+	 * 
+	 * @param oldArray
+	 * @return
+	 */
+
+	public static int[] removeZero(int[] oldArray) {
+		int[] newArray = null;
+		if (oldArray != null) {
+			newArray = new int[oldArray.length];
+			int size = 0;
+			for (int i = 0; i < oldArray.length; i++) {
+				if (oldArray[i] != 0) {
+					newArray[size] = oldArray[i];
+					size++;
+				}
+			}
+			newArray = Arrays.copyOf(newArray, size);
+		}
+		return newArray;
+	}
+
+	/**
+	 * 给定两个已经排序好的整形数组， a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素， 并且仍然是有序的 例如 a1 =
+	 * [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意： 已经消除了重复
+	 * 
+	 * @param array1
+	 * @param array2
+	 * @return
+	 */
+
+	public static int[] merge(int[] array1, int[] array2) {
+		int[] newArray = null;
+		if (array1 != null && array2 != null) {
+			int size = 0;
+
+			// index1、index2表示array1和array2数组的比较索引
+			int index1 = 0, index2 = 0;
+			newArray = new int[array1.length + array2.length];
+
+			while (index1 < array1.length && index2 < array2.length) {
+				if (array1[index1] == array2[index2]) {
+					newArray[size++] = array1[index1];
+					index1++;
+					index2++;
+				} else if (array1[index1] < array2[index2]) {
+					// 数组array1去重
+					if (size > 0 && array1[index1] == newArray[size - 1]) {
+						size--;
+					}
+					newArray[size++] = array1[index1];
+					index1++;
+				} else {
+					// 数组array2去重
+					if (size > 0 && array2[index2] == newArray[size - 1]) {
+						size--;
+					}
+					newArray[size++] = array2[index2];
+					index2++;
+				}
+			}
+
+			// 将数组array1剩下的元素放入
+			while (index1 < array1.length) {
+				newArray[size++] = array1[index1++];
+			}
+
+			// 将数组array2剩下的元素放入
+			while (index2 < array2.length) {
+				newArray[size++] = array2[index2++];
+			}
+
+			// 合并后有序数组
+			newArray = Arrays.copyOf(newArray, size);
+		}
+		return newArray;
+	}
+
+	/**
+	 * 把一个已经存满数据的数组 oldArray的容量进行扩展， 扩展后的新数据大小为oldArray.length + size
+	 * 注意，老数组的元素在新数组中需要保持 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为
+	 * [2,3,6,0,0,0]
+	 * 
+	 * @param oldArray
+	 * @param size
+	 * @return
+	 */
+	public static int[] grow(int[] oldArray, int size) {
+		int[] newArray = null;
+		if (oldArray != null) {
+			newArray = new int[oldArray.length + size];
+			for (int i = 0; i < oldArray.length; i++) {
+				newArray[i] = oldArray[i];
+			}
+		}
+		return newArray;
+	}
+
+	/**
+	 * 斐波那契数列为：1，1，2，3，5，8，13，21...... ，给定一个最大值， 返回小于该值的数列 例如， max = 15 ,
+	 * 则返回的数组应该为 [1，1，2，3，5，8，13] max = 1, 则返回空数组 []
+	 * 
+	 * @param max
+	 * @return
+	 */
+	public static int[] fibonacci(int max) {
+
+		// 计算方法：f(n) = f(n-1) + f(n-2) 采用数组计算
+		int[] result = null;
+		if (max <= 1) {
+			result = new int[] {};
+		} else {
+			int i = 2;
+			result = new int[max];
+			result[0] = result[1] = 1;
+			for (; i < max; i++) {
+				if (result[i - 1] + result[i - 2] < max) {
+					result[i] = result[i - 1] + result[i - 2];
+				} else {
+					break;
+				}
+			}
+			result = Arrays.copyOf(result, i);
+		}
+		return result;
+	}
+
+	/**
+	 * 返回小于给定最大值max的所有素数数组 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19]
+	 * 
+	 * @param max
+	 * @return
+	 */
+	public static int[] getPrimes(int max) {
+		int[] newArray = new int[] {};
+		if (max > 2) {
+			newArray = new int[max];
+			int size = 0, j = 0;
+			for (int i = 2; i < max; i++) {
+				for (j = 2; j < i / 2 + 1; j++) {
+					if (i % j == 0) {
+						break;
+					}
+				}
+
+				if (j == i / 2 + 1) {
+					newArray[size++] = i;
+				}
+			}
+			newArray = Arrays.copyOf(newArray, size);
+		}
+		return newArray;
+	}
+
+	/**
+	 * 所谓“完数”， 是指这个数恰好等于它的因子之和，例如6=1+2+3 给定一个最大值max， 返回一个数组， 数组中是小于max 的所有完数
+	 * 
+	 * @param max
+	 * @return
+	 */
+	public static int[] getPerfectNumbers(int max) {
+		int[] newArray = new int[] {};
+		if (max > 0) {
+			newArray = new int[max];
+			int size = 0, sum = 0;
+			for (int i = 1; i < max; i++) {
+				sum = 0;
+				for (int j = 1; j < i / 2 + 1; j++) {
+					if (i % j == 0) {
+						sum += j;
+					}
+				}
+				if (i == sum) {
+					newArray[size++] = i;
+				}
+			}
+			newArray = Arrays.copyOf(newArray, size);
+		}
+		return newArray;
+	}
+
+	/**
+	 * 用seperator 把数组 array给连接起来 例如array= [3,8,9], seperator = "-" 则返回值为"3-8-9"
+	 * 
+	 * @param array
+	 * @param seperator
+	 * @return
+	 */
+	public static String join(int[] array, String seperator) {
+		String joinResult = null;
+		if (array != null) {
+			joinResult = "";
+			for (int i = 0; i < array.length; i++) {
+				joinResult += array[i] + seperator;
+			}
+			joinResult = joinResult.equals("") ? "" : joinResult.substring(0, joinResult.length() - 1);
+		}
+		return joinResult;
+	}
+
+	public static void main(String[] args) {
+		int[] a = new ArrayUtil().getPerfectNumbers(1000);
+		for (int i = 0; i < a.length; i++) {
+			System.out.println(a[i]);
+		}
+
+		// [2,3,5,7,11,13,17,19]
+		a = new ArrayUtil().getPrimes(20);
+		for (int i = 0; i < a.length; i++) {
+			System.out.println(a[i]);
+		}
+	}
+}

group01/1298552064/src/week02/litestruts/LoginAction.java

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+package week02.litestruts;
+
+/**
+ * 这是一个用来展示登录的业务类， 其中的用户名和密码都是硬编码的。
+ * 
+ * @author liuxin
+ *
+ */
+public class LoginAction {
+	private String name;
+	private String password;
+	private String message;
+
+	public String getName() {
+		return name;
+	}
+
+	public String getPassword() {
+		return password;
+	}
+
+	public String execute() {
+		if ("test".equals(name) && "1234".equals(password)) {
+			this.message = "login successful";
+			return "success";
+		}
+		this.message = "login failed,please check your user/pwd";
+		return "fail";
+	}
+
+	public void setName(String name) {
+		this.name = name;
+	}
+
+	public void setPassword(String password) {
+		this.password = password;
+	}
+
+	public String getMessage() {
+		return this.message;
+	}
+}