Generate specialized Functional Interfaces for Function{0,1,2} #16
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As exerciced in the test, a specialized (Int => Int) function can
be implemented by extending the functional interface
`JFunction1$mcII$sp`.
Representative example of the generated code:
```java
public interface JFunction0$mcV$sp extends JFunction0 {
abstract void apply$mcV$sp();
default Object apply() { apply$mcV$sp(); return scala.runtime.BoxedUnit.UNIT; }
}
public interface JFunction0$mcZ$sp extends JFunction0 {
abstract boolean apply$mcZ$sp();
default Object apply() { return (Boolean) apply$mcZ$sp(); }
}
public interface JFunction1$mcDD$sp extends JFunction1 {
abstract double apply$mcDD$sp(double v1);
default Object apply(Object t) { return (Double) apply$mcDD$sp((Double) t); }
}
public interface JFunction1$mcVD$sp extends JFunction1 {
abstract void apply$mcVD$sp(double v1);
default Object apply(Object t) { apply$mcVD$sp((Double) t); return scala.runtime.BoxedUnit.UNIT; }
}
public final class JFunction {
private JFunction() {}
public static <R> scala.Function0<R> func(JFunction0<R> f) { return f; }
public static scala.Function0<BoxedUnit> proc(JProcedure0 p) { return p; }
public static scala.Function0<BoxedUnit> procSpecialized(JFunction0$mcV$sp f) { return f; }
public static scala.Function0<Byte> funcSpecialized(JFunction0$mcB$sp f) { return f; }
public static scala.Function0<Short> funcSpecialized(JFunction0$mcS$sp f) { return f; }
public static scala.Function0<Integer> funcSpecialized(JFunction0$mcI$sp f) { return f; }
public static scala.Function0<Long> funcSpecialized(JFunction0$mcJ$sp f) { return f; }
public static scala.Function0<Character> funcSpecialized(JFunction0$mcC$sp f) { return f; }
public static scala.Function0<Float> funcSpecialized(JFunction0$mcF$sp f) { return f; }
public static scala.Function0<Double> funcSpecialized(JFunction0$mcD$sp f) { return f; }
public static scala.Function0<Boolean> funcSpecialized(JFunction0$mcZ$sp f) { return f; }
public static <T1, R> scala.Function1<T1, R> func(JFunction1<T1, R> f) { return f; }
public static <T1> scala.Function1<T1, BoxedUnit> proc(JProcedure1<T1> p) { return p; }
public static scala.Function1<Integer, BoxedUnit> procSpecialized(JFunction1$mcVI$sp f) { return f; }
public static scala.Function1<Integer, Boolean> funcSpecialized(JFunction1$mcZI$sp f) { return f; }
```
I've also modified the code generator to create `JProcedure0` (which
was an oversight), and to switch to Scala 2.11.4.
Handy when varying other build parameters, such as `scalaVersion`, results in unavailabilty of genjavadoc or in a Scaladoc bug.
retronym
added a commit
that referenced
this pull request
Nov 17, 2014
Generate specialized Functional Interfaces for Function{0,1,2}
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