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【Arai60】24問目 108_Convert Sorted Array to Binary Search Tree #24
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,45 @@ | ||
| # DFS | ||
| class Solution: | ||
| def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]: | ||
| def helper(left, right): | ||
| if left > right: | ||
| return None | ||
| mid = (left + right) // 2 | ||
| node = TreeNode(nums[mid]) | ||
| node.left = helper(left, mid - 1) | ||
| node.right = helper(mid + 1, right) | ||
| return node | ||
|
|
||
| return helper(0, len(nums) - 1) | ||
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|
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| # BFS | ||
| class Solution: | ||
| def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]: | ||
| mid = (len(nums) - 1) // 2 | ||
| root = TreeNode(nums[mid]) | ||
| queue = deque([(root, (0, mid - 1), (mid + 1, len(nums) - 1))]) | ||
| while queue: | ||
| node, left_range, right_range = queue.popleft() | ||
| if left_range[0] <= left_range[1]: | ||
|
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 関数に切り出すとかしても良いかも。うまく切り出せるかは試してないですが。 |
||
| left_mid = (left_range[0] + left_range[1]) // 2 | ||
| node.left = TreeNode(nums[left_mid]) | ||
| queue.append( | ||
| ( | ||
| node.left, | ||
| (left_range[0], left_mid - 1), | ||
| (left_mid + 1, left_range[1]), | ||
| ) | ||
| ) | ||
| if right_range[0] <= right_range[1]: | ||
| right_mid = (right_range[0] + right_range[1]) // 2 | ||
| node.right = TreeNode(nums[right_mid]) | ||
| queue.append( | ||
| ( | ||
| node.right, | ||
| (right_range[0], right_mid - 1), | ||
| (right_mid + 1, right_range[1]), | ||
| ) | ||
| ) | ||
|
|
||
| return root | ||
| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,44 @@ | ||
| # DFSでnodeを作成していく | ||
| # helper関数を使わない形に修正 | ||
| class Solution: | ||
| def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]: | ||
| if not nums: | ||
| return None | ||
| mid = (len(nums) - 1) // 2 | ||
| node = TreeNode(val=nums[mid]) | ||
| node.left = self.sortedArrayToBST(nums[:mid]) | ||
| node.right = self.sortedArrayToBST(nums[mid + 1 :]) | ||
| return node | ||
|
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||
|
|
||
| # BFS | ||
| # queueの中身をlistに変更 | ||
| class Solution: | ||
| def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]: | ||
| mid = (len(nums) - 1) // 2 | ||
| root = TreeNode(nums[mid]) | ||
|
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. LeetCodeの制約ではlen(nums) >= 1が保証されてますが、空配列だとIndexErrorになりますね。 |
||
| queue = deque([(root, nums[:mid], nums[mid + 1 :])]) | ||
| while queue: | ||
| node, left_nums, right_nums = queue.popleft() | ||
| if left_nums: | ||
| left_mid = (len(left_nums) - 1) // 2 | ||
| node.left = TreeNode(left_nums[left_mid]) | ||
| queue.append( | ||
| ( | ||
| node.left, | ||
| left_nums[:left_mid], | ||
| left_nums[left_mid + 1 :], | ||
| ) | ||
| ) | ||
| if right_nums: | ||
| right_mid = (len(right_nums) - 1) // 2 | ||
| node.right = TreeNode(right_nums[right_mid]) | ||
| queue.append( | ||
| ( | ||
| node.right, | ||
| right_nums[:right_mid], | ||
| right_nums[right_mid + 1 :], | ||
| ) | ||
| ) | ||
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| return root | ||
| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,14 @@ | ||
| # DFS | ||
| # level1と同じものが一番シンプルで書きやすい | ||
| class Solution: | ||
| def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]: | ||
| def helper(left, right): | ||
| if left > right: | ||
| return None | ||
| mid = (left + right) // 2 | ||
|
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. コードからは意識してるか分からなかったので念の為共有です。範囲に含まれる要素が偶数のときに真ん中が存在しないのでmidの選択により左と右のどちらをrootにするかが決まりますね。 |
||
| node = TreeNode(nums[mid]) | ||
| node.left = helper(left, mid - 1) | ||
| node.right = helper(mid + 1, right) | ||
| return node | ||
|
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| return helper(0, len(nums) - 1) | ||
|
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. helperでも良いんですが具体的な命名をしても良いかもですね。 |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,85 @@ | ||
| # DFSでnodeを作成していく(再帰①) | ||
| class Solution: | ||
| def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]: | ||
| if not nums: | ||
| return None | ||
| mid = (len(nums) - 1) // 2 | ||
| node = TreeNode(val=nums[mid]) | ||
| node.left = self.sortedArrayToBST(nums[:mid]) # 帰りがけの作業 | ||
| node.right = self.sortedArrayToBST(nums[mid + 1 :]) # 帰りがけの作業 | ||
| return node | ||
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| # DFSでnodeを作成していく(再帰②) | ||
| # 呼び出された側でnodeの書き込みまで行う | ||
| # rootだけは別途作成が必要 | ||
| class Solution: | ||
| def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]: | ||
|
|
||
| def helper(node, index, nums): | ||
| left_nums = nums[:index] | ||
| if left_nums: | ||
| left_mid = (len(left_nums) - 1) // 2 | ||
| node.left = TreeNode(val=left_nums[left_mid]) | ||
| helper(node.left, left_mid, left_nums) | ||
| right_nums = nums[index + 1 :] | ||
| if right_nums: | ||
| right_mid = (len(right_nums)) // 2 | ||
| node.right = TreeNode(val=right_nums[right_mid]) | ||
| helper(node.right, right_mid, right_nums) | ||
|
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| mid = (len(nums) - 1) // 2 | ||
| root = TreeNode(val=nums[mid]) | ||
| helper(root, mid, nums) | ||
| return root | ||
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|
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| # 再帰②をstackで実装 | ||
| class Solution: | ||
| def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]: | ||
| mid = (len(nums) - 1) // 2 | ||
| root = TreeNode(val=nums[mid]) | ||
| stack = [(root, mid, nums)] | ||
|
|
||
| while stack: | ||
| node, index, nums_list = stack.pop() | ||
| left_nums = nums_list[:index] | ||
| if left_nums: | ||
| left_mid = (len(left_nums) - 1) // 2 | ||
| node.left = TreeNode(val=left_nums[left_mid]) | ||
| stack.append((node.left, left_mid, left_nums)) | ||
| right_nums = nums_list[index + 1 :] | ||
| if right_nums: | ||
| right_mid = (len(right_nums)) // 2 | ||
| node.right = TreeNode(val=right_nums[right_mid]) | ||
| stack.append((node.right, right_mid, right_nums)) | ||
|
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| return root | ||
|
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|
|
||
| # BFS | ||
| # queueの中身をlistに変更 | ||
| class Solution: | ||
| def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]: | ||
|
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||
| def create_child(child_nums): | ||
| if not child_nums: | ||
| return 0, None | ||
| mid = (len(child_nums) - 1) // 2 | ||
| child = TreeNode(child_nums[mid]) | ||
| return mid, child | ||
|
|
||
| if not nums: | ||
| return None | ||
| mid = (len(nums) - 1) // 2 | ||
| root = TreeNode(nums[mid]) | ||
| queue = deque([(root, nums[:mid], nums[mid + 1 :])]) | ||
| while queue: | ||
| parent, left_nums, right_nums = queue.popleft() | ||
| left_mid, parent.left = create_child(left_nums) | ||
| if parent.left: | ||
| queue.append((parent.left, left_nums[:left_mid], left_nums[left_mid + 1 :])) | ||
| right_mid, parent.right = create_child(right_nums) | ||
| if parent.right: | ||
| queue.append((parent.right, right_nums[:right_mid], right_nums[right_mid + 1 :])) | ||
| return root |
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parentとかでもいいかも。
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BFSの方はparentの方が分かりやすいですね。