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Original file line number Diff line number Diff line change
@@ -0,0 +1,45 @@
# DFS
class Solution:
def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]:
def helper(left, right):
if left > right:
return None
mid = (left + right) // 2
node = TreeNode(nums[mid])
node.left = helper(left, mid - 1)
node.right = helper(mid + 1, right)
return node

return helper(0, len(nums) - 1)


# BFS
class Solution:
def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]:
mid = (len(nums) - 1) // 2
root = TreeNode(nums[mid])
queue = deque([(root, (0, mid - 1), (mid + 1, len(nums) - 1))])
while queue:
node, left_range, right_range = queue.popleft()
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parentとかでもいいかも。

Suggested change
node, left_range, right_range = queue.popleft()
parent, left_range, right_range = queue.popleft()

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BFSの方はparentの方が分かりやすいですね。

if left_range[0] <= left_range[1]:
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関数に切り出すとかしても良いかも。うまく切り出せるかは試してないですが。

left_mid = (left_range[0] + left_range[1]) // 2
node.left = TreeNode(nums[left_mid])
queue.append(
(
node.left,
(left_range[0], left_mid - 1),
(left_mid + 1, left_range[1]),
)
)
if right_range[0] <= right_range[1]:
right_mid = (right_range[0] + right_range[1]) // 2
node.right = TreeNode(nums[right_mid])
queue.append(
(
node.right,
(right_range[0], right_mid - 1),
(right_mid + 1, right_range[1]),
)
)

return root
Original file line number Diff line number Diff line change
@@ -0,0 +1,44 @@
# DFSでnodeを作成していく
# helper関数を使わない形に修正
class Solution:
def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]:
if not nums:
return None
mid = (len(nums) - 1) // 2
node = TreeNode(val=nums[mid])
node.left = self.sortedArrayToBST(nums[:mid])
node.right = self.sortedArrayToBST(nums[mid + 1 :])
return node


# BFS
# queueの中身をlistに変更
class Solution:
def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]:
mid = (len(nums) - 1) // 2
root = TreeNode(nums[mid])
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LeetCodeの制約ではlen(nums) >= 1が保証されてますが、空配列だとIndexErrorになりますね。

queue = deque([(root, nums[:mid], nums[mid + 1 :])])
while queue:
node, left_nums, right_nums = queue.popleft()
if left_nums:
left_mid = (len(left_nums) - 1) // 2
node.left = TreeNode(left_nums[left_mid])
queue.append(
(
node.left,
left_nums[:left_mid],
left_nums[left_mid + 1 :],
)
)
if right_nums:
right_mid = (len(right_nums) - 1) // 2
node.right = TreeNode(right_nums[right_mid])
queue.append(
(
node.right,
right_nums[:right_mid],
right_nums[right_mid + 1 :],
)
)

return root
Original file line number Diff line number Diff line change
@@ -0,0 +1,14 @@
# DFS
# level1と同じものが一番シンプルで書きやすい
class Solution:
def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]:
def helper(left, right):
if left > right:
return None
mid = (left + right) // 2
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コードからは意識してるか分からなかったので念の為共有です。範囲に含まれる要素が偶数のときに真ん中が存在しないのでmidの選択により左と右のどちらをrootにするかが決まりますね。

node = TreeNode(nums[mid])
node.left = helper(left, mid - 1)
node.right = helper(mid + 1, right)
return node

return helper(0, len(nums) - 1)
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helperでも良いんですが具体的な命名をしても良いかもですね。

Original file line number Diff line number Diff line change
@@ -0,0 +1,85 @@
# DFSでnodeを作成していく(再帰①)
class Solution:
def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]:
if not nums:
return None
mid = (len(nums) - 1) // 2
node = TreeNode(val=nums[mid])
node.left = self.sortedArrayToBST(nums[:mid]) # 帰りがけの作業
node.right = self.sortedArrayToBST(nums[mid + 1 :]) # 帰りがけの作業
return node


# DFSでnodeを作成していく(再帰②)
# 呼び出された側でnodeの書き込みまで行う
# rootだけは別途作成が必要
class Solution:
def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]:

def helper(node, index, nums):
left_nums = nums[:index]
if left_nums:
left_mid = (len(left_nums) - 1) // 2
node.left = TreeNode(val=left_nums[left_mid])
helper(node.left, left_mid, left_nums)
right_nums = nums[index + 1 :]
if right_nums:
right_mid = (len(right_nums)) // 2
node.right = TreeNode(val=right_nums[right_mid])
helper(node.right, right_mid, right_nums)

mid = (len(nums) - 1) // 2
root = TreeNode(val=nums[mid])
helper(root, mid, nums)
return root


# 再帰②をstackで実装
class Solution:
def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]:
mid = (len(nums) - 1) // 2
root = TreeNode(val=nums[mid])
stack = [(root, mid, nums)]

while stack:
node, index, nums_list = stack.pop()
left_nums = nums_list[:index]
if left_nums:
left_mid = (len(left_nums) - 1) // 2
node.left = TreeNode(val=left_nums[left_mid])
stack.append((node.left, left_mid, left_nums))
right_nums = nums_list[index + 1 :]
if right_nums:
right_mid = (len(right_nums)) // 2
node.right = TreeNode(val=right_nums[right_mid])
stack.append((node.right, right_mid, right_nums))

return root


# BFS
# queueの中身をlistに変更
class Solution:
def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]:

def create_child(child_nums):
if not child_nums:
return 0, None
mid = (len(child_nums) - 1) // 2
child = TreeNode(child_nums[mid])
return mid, child

if not nums:
return None
mid = (len(nums) - 1) // 2
root = TreeNode(nums[mid])
queue = deque([(root, nums[:mid], nums[mid + 1 :])])
while queue:
parent, left_nums, right_nums = queue.popleft()
left_mid, parent.left = create_child(left_nums)
if parent.left:
queue.append((parent.left, left_nums[:left_mid], left_nums[left_mid + 1 :]))
right_mid, parent.right = create_child(right_nums)
if parent.right:
queue.append((parent.right, right_nums[:right_mid], right_nums[right_mid + 1 :]))
return root