BFS-1 Solutions

[dbkuppagiri]

No description provided.

[super30admin]

Strengths:

• The solution correctly implements level order traversal using BFS.
• The use of an index pointer to avoid expensive shift() operations is efficient and demonstrates good understanding of JavaScript performance.
• The code is clean, well-commented, and easy to follow.

Areas for Improvement:

• The submission includes an unrelated file (canFinish.js). Ensure that only the relevant solution is provided for the problem being evaluated.
• In the levelOrder function, the variable currRoot might be slightly misleading since it represents a node, not necessarily the root. Consider renaming it to node or currentNode for clarity.
• The inner loop uses currLength to process the current level. This is correct, but note that the queue length increases as children are added. The approach is correct, but it's important to understand that the initial queue.length - idx gives the number of nodes at the current level.

Overall, the solution is efficient and correct. The minor naming issue does not affect functionality.