solved

[jeetusingh247]

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[super30admin]

Your solution for the level order traversal problem is excellent. You have correctly implemented the BFS approach using a queue, and your code is clean and well-commented. The time and space complexity analysis you provided is accurate.

One minor suggestion: In Java, it is common to use the interface type (e.g., Queue<TreeNode> q = new LinkedList<>();) for declaring collections, which you have done correctly. However, you might consider using the diamond operator (<>) consistently, which you are already doing. Also, note that the comment "Space: O(n/2) --> O(n)" is correct, but it's more precise to say that the maximum space used by the queue is the maximum width of the tree, which in the worst case (a complete binary tree) is about n/2.

Overall, great job!

[super30admin]

Your solution for the Level Order Traversal problem is excellent. You have correctly implemented the BFS approach using a queue, and your code is clean and well-commented. The time and space complexity are optimal.

One minor suggestion: In the comments, you mentioned that you can also solve it using DFS. While that is true, DFS for level order traversal typically requires tracking the level and might be less intuitive than BFS for this problem. However, your BFS solution is the standard and most efficient approach.

Keep up the good work! Your understanding of the problem and implementation are solid.