std.format: Prepare to add %g (step 1).#7810
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This was referenced Mar 1, 2021
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This step is the decision, if a %e-like or a %f-like output should be created. According to the specs
%gproduces the shorter of the two. That's wrong. The cutting points depend on the requested precision, roughly between10^^precisionand0.0001%fis used and%eelse (sign ignored here). Different rounding modes make this a little bit more difficult, but doable. The result looks like this:Unfortunately, for some corner cases, this does not result in an identical choice, compared with
snprintf, which means, in really rare circumstances, this could break code. (I still advocate for using this, see below.)To get around this, I added own functions for
10.0 ^^ +nand10.0 ^^ -n, which use integer arithmetics instead of floating point arithmetics.A second problem arises now: D may use internally
realsto do the calculation, but the size ofrealmay vary, depending on the computer used. All in all, we still cannot rely on anything and have to continue to simulate floating point math, using integers. I did this with the functionslesswhich are easy to implement. To be really sure, we would also need a simulation of-and*, which is much more complicated. Further, I'm not sure, if this all works withreal==double-reals.All in all, I would prefer to just use the code I gave above and to accept, that there are rare corner cases, where the proposed implementation differs from the one of
snprintf. (It would mean, that we have to loosen the added unittests a little bit, by adding some morenextUp/nextDown, leaving a gap of uncertainity.)What do you think?